Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
a(b(c(x1))) → c(b(a(x1)))
C(B(A(x1))) → A(B(C(x1)))
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
c(C(x1)) → x1
C(c(x1)) → x1
Q is empty.
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
a(b(c(x1))) → c(b(a(x1)))
C(B(A(x1))) → A(B(C(x1)))
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
c(C(x1)) → x1
C(c(x1)) → x1
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
a(b(c(x1))) → c(b(a(x1)))
C(B(A(x1))) → A(B(C(x1)))
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
c(C(x1)) → x1
C(c(x1)) → x1
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
a(b(c(x1))) → c(b(a(x1)))
c(C(x1)) → x1
C(c(x1)) → x1
Used ordering:
Polynomial interpretation [25]:
POL(A(x1)) = x1
POL(B(x1)) = x1
POL(C(x1)) = x1
POL(a(x1)) = 2·x1
POL(b(x1)) = x1
POL(c(x1)) = 1 + 2·x1
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
C(B(A(x1))) → A(B(C(x1)))
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
C(B(A(x1))) → A(B(C(x1)))
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
b(a(C(x1))) → C(a(b(x1)))
c(A(B(x1))) → B(A(c(x1)))
a(A(x1)) → x1
A(a(x1)) → x1
b(B(x1)) → x1
B(b(x1)) → x1
Used ordering:
Polynomial interpretation [25]:
POL(A(x1)) = 1 + 2·x1
POL(B(x1)) = x1
POL(C(x1)) = x1
POL(a(x1)) = 2 + 2·x1
POL(b(x1)) = 1 + 2·x1
POL(c(x1)) = 2·x1
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
C(B(A(x1))) → A(B(C(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
C(B(A(x1))) → A(B(C(x1)))
A(c(b(x1))) → b(c(A(x1)))
B(C(a(x1))) → a(C(B(x1)))
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
C(B(A(x1))) → A(B(C(x1)))
B(C(a(x1))) → a(C(B(x1)))
Used ordering:
Polynomial interpretation [25]:
POL(A(x1)) = 2 + x1
POL(B(x1)) = 2·x1
POL(C(x1)) = 2 + 2·x1
POL(a(x1)) = 1 + x1
POL(b(x1)) = x1
POL(c(x1)) = x1
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
A(c(b(x1))) → b(c(A(x1)))
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
A(c(b(x1))) → b(c(A(x1)))
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
A(c(b(x1))) → b(c(A(x1)))
Used ordering:
Polynomial interpretation [25]:
POL(A(x1)) = 2·x1
POL(b(x1)) = 2 + x1
POL(c(x1)) = 1 + 2·x1
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RisEmptyProof
Q restricted rewrite system:
R is empty.
Q is empty.
The TRS R is empty. Hence, termination is trivially proven.